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Chemistry

Fundamentals of Chemistry

4,771 words, 10 sections

This chapter is the quantitative spine of the chemistry paper, and it is examined more heavily than any other unit in the subject. It has produced 264 distinct questions across 88 official papers between 2000 and 2026, set by Balochistan, DUHS, Federal, KMU, NUMS and UHS, with 1149 questions active in the practice bank and a mean item difficulty of 2.14. Almost all of that weight sits in one place: 205 of the 264 questions belong to stoichiometry and the mole concept, with empirical and molecular formulas adding 36 and limiting reagents with percentage yield adding 23. A student who can move confidently between mass, moles, particles and gas volume, who spots the limiting reagent before reaching the calculator, and who can turn a percentage composition into a formula will collect marks that most of the cohort leaves on the table. Chemistry contributes 45 of the 180 paper marks, and this chapter is where the arithmetic marks live.

The mole is the amount of a substance that contains as many elementary entities as there are atoms in 12 g\text{12 g} of carbon-12. Those entities are not always atoms; they can be molecules, formula units, ions or electrons, and the number of them in one mole is fixed at Avogadro's number, NA=6.02×1023N_A = 6.02 \times 10^{23} (the exact value is 6.02214179×1023 mol−16.02214179 \times 10^{23}\ \text{mol}^{-1}, and papers almost always use the rounded form). Carbon-12 is the reference standard against which relative masses are measured, so one mole of CCl4\text{CCl}_4 carries 6.02×10236.02 \times 10^{23} molecules while one mole of Na+\text{Na}^+ carries 6.02×10236.02 \times 10^{23} ions. The identity of the particle changes; the count never does.

Molar mass, written MM, is the mass of one mole expressed in grams, and its unit is g mol−1\text{g mol}^{-1}. It is built by adding the atomic masses of the component atoms, so the molar mass of CCl4\text{CCl}_4 is 12.0+4(35.5)=154.0 g mol−112.0 + 4(35.5) = 154.0\ \text{g mol}^{-1}. Because the same single number is shared by every mole of every substance, the amount of a sample follows directly from its mass: n=m/Mn = m/M. This is the conversion that opens every calculation in the rest of the chapter. A single atom weighs its molar mass divided by NAN_A, which is why one atom of sodium is 1/NA1/N_A mole and not 23 g23\ \text{g}.

Be careful with the mass unit itself. The atomic mass unit is 1.66×10−27 kg1.66 \times 10^{-27}\ \text{kg}, not a mass of hydrogen and not a multiple of the electron mass. The mass shown on the periodic table is an average over the isotopes, so no individual neon atom in a sample weighs 20.18 amu; that figure is the average atomic mass and it belongs to the bulk, not to any one atom.

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